z^2-z+(4+2i)=0

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Solution for z^2-z+(4+2i)=0 equation:


Simplifying
z2 + -1z + (4 + 2i) = 0

Remove parenthesis around (4 + 2i)
z2 + -1z + 4 + 2i = 0

Reorder the terms:
4 + 2i + -1z + z2 = 0

Solving
4 + 2i + -1z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 2i + -1z + -4 + z2 = 0 + -4

Reorder the terms:
4 + -4 + 2i + -1z + z2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 2i + -1z + z2 = 0 + -4
2i + -1z + z2 = 0 + -4

Combine like terms: 0 + -4 = -4
2i + -1z + z2 = -4

Add 'z' to each side of the equation.
2i + -1z + z + z2 = -4 + z

Combine like terms: -1z + z = 0
2i + 0 + z2 = -4 + z
2i + z2 = -4 + z

Add '-1z2' to each side of the equation.
2i + z2 + -1z2 = -4 + z + -1z2

Combine like terms: z2 + -1z2 = 0
2i + 0 = -4 + z + -1z2
2i = -4 + z + -1z2

Divide each side by '2'.
i = -2 + 0.5z + -0.5z2

Simplifying
i = -2 + 0.5z + -0.5z2

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